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A force of 10 N acts on a body for 3 m in the same direction as the displacement. What is the work done?

5 J

15 J

25 J

30 J

Work is the transfer of energy when a force moves an object, and it is calculated as W = F d cos theta, where theta is the angle between the force and the displacement. Here the force and the displacement point in the same direction, so theta = 0 and cos theta = 1. The force is 10 N and the displacement is 3 m, so the work done is W = 10 N × 3 m × 1 = 30 J. Therefore, 30 joules of work are done. The other values would come from using a smaller effective distance or misapplying the cosine factor, which isn’t the case here since the force aligns with the motion.

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